answer this one
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in most cases those riddles shouldn't be used word by word. maybe one "no" is not a "number" it may be "no" like in "not yes".
or it may mean something like 10 = 2 is one number
and
01 = 1 the other one.
the product of 10 and 01 (seen as strings not as numbers) is 1001.
But that should not be the right answer, because 01 = 1 is no prime number as said before.
I wanna say, maybe the problem is not to solve mathematically
or it may mean something like 10 = 2 is one number
and
01 = 1 the other one.
the product of 10 and 01 (seen as strings not as numbers) is 1001.
But that should not be the right answer, because 01 = 1 is no prime number as said before.
I wanna say, maybe the problem is not to solve mathematically

Re:"Board Games"
Nice question and I think 11*91 is my answer,there may be many.
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Ricky Conway
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Ricky Conway
Re:"Board Games"
91 is not prime, it is divisible by 7rconway wrote:Nice question and I think 11*91 is my answer,there may be many.
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Ricky Conway
Mathematically spoken you need to do a prime factorisation in order to solve this problem. 
1001 = 7 * 143 = 7 * 11 * 13
So you can see: There are three prime numbers necessary to get a product of 1001. It's not possible with only two prime numbers.
Generally spoken a product is: a * b = x
Our x is 1001. So you can say that whether a or b has to be below the radical of 1001, otherwise the product would always be larger than 1001.
The radical of 1001 is ~31.6386.
So we simply can prove all prime numbers below 31.6386 (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31).
Find one of them that divides 1001 integer. That one would be our "a". The result of 1001/"prime number (= a)" is our second multiplier, our "b". In our case "b" must be a prime number.
And unfortunately you will not find our "b" as a prime number.
Thus there is no result for this task.

1001 = 7 * 143 = 7 * 11 * 13
So you can see: There are three prime numbers necessary to get a product of 1001. It's not possible with only two prime numbers.
Generally spoken a product is: a * b = x
Our x is 1001. So you can say that whether a or b has to be below the radical of 1001, otherwise the product would always be larger than 1001.
The radical of 1001 is ~31.6386.
So we simply can prove all prime numbers below 31.6386 (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31).
Find one of them that divides 1001 integer. That one would be our "a". The result of 1001/"prime number (= a)" is our second multiplier, our "b". In our case "b" must be a prime number.
And unfortunately you will not find our "b" as a prime number.
Thus there is no result for this task.